What is the answer to (t-7)^2=(t+7)^2-112 ?

The answer to (t-7)^2=(t+7)^2-112 is t=4

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(t-7)^2=(t+7)^2-112

(t - 7)^{2} = (t + 7)^{2} - 112

t = 4

Solution steps

(t - 7)^{2} = (t + 7)^{2} - 112

Expand

(t - 7)^{2} : t^{2} - 14 t + 49

Expand

(t + 7)^{2} - 112 : t^{2} + 14 t - 63

t^{2} - 14 t + 49 = t^{2} + 14 t - 63

Move

49

to the right side

t^{2} - 14 t = t^{2} + 14 t - 112

Subtract

t^{2} + 14 t

from both sides

t^{2} - 14 t - (t^{2} + 14 t) = t^{2} + 14 t - 112 - (t^{2} + 14 t)

Simplify

- 28 t = - 112

Divide both sides by

- 28

t = 4

3 (x - 1) - 2 (x + 1) + 4 (x - 2) = 0

4 - 3 x = 2 + 5 x

p^{2} + 16 p - 22 = 0

- 3 x + 18 < 9

∣ 2 x ∣ \geq 6

What is the answer to (t-7)^2=(t+7)^2-112 ?
The answer to (t-7)^2=(t+7)^2-112 is t=4
Solve for t: (t-7)^2=(t+7)^2-112
The solution is t=4