What is the answer to 3(x-1)-2(x+1)+4(x-2)=0 ?

The answer to 3(x-1)-2(x+1)+4(x-2)=0 is x= 13/5

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3(x-1)-2(x+1)+4(x-2)=0

3 (x - 1) - 2 (x + 1) + 4 (x - 2) = 0

x = \frac{13}{5}

Decimal Notation

x = 2.6

Solution steps

3 (x - 1) - 2 (x + 1) + 4 (x - 2) = 0

Expand

3 (x - 1) - 2 (x + 1) + 4 (x - 2) : 5 x - 13

5 x - 13 = 0

Move

13

to the right side

5 x = 13

Divide both sides by

5

x = \frac{13}{5}

4 - 3 x = 2 + 5 x

p^{2} + 16 p - 22 = 0

- 3 x + 18 < 9

∣ 2 x ∣ \geq 6

y^{2} - 81 = 0

What is the answer to 3(x-1)-2(x+1)+4(x-2)=0 ?
The answer to 3(x-1)-2(x+1)+4(x-2)=0 is x= 13/5
Solve for x: 3(x-1)-2(x+1)+4(x-2)=0
The solution is x= 13/5