What are the solutions to the equation 4a^2+20a=-9 ?

The solutions to the equation 4a^2+20a=-9 are a=-1/2 ,a=-9/2

Find the zeros of 4a^2+20a=-9

The zeros of 4a^2+20a=-9 are a=-1/2 ,a=-9/2

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4 a^{2} + 20 a = - 9

a = - \frac{1}{2}, a = - \frac{9}{2}

Decimal Notation

a = - 0.5, a = - 4.5

Solution steps

4 a^{2} + 20 a = - 9

Move

9

to the left side

4 a^{2} + 20 a + 9 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 4 \cdot 9}{2 \cdot 4}

2 0^{2} - 4 \cdot 4 \cdot 9 = 16

a_{1, 2} = \frac{- 20 \pm 16}{2 \cdot 4}

Separate the solutions

a_{1} = \frac{- 20 + 16}{2 \cdot 4}, a_{2} = \frac{- 20 - 16}{2 \cdot 4}

a = \frac{- 20 + 16}{2 \cdot 4} : - \frac{1}{2}

a = \frac{- 20 - 16}{2 \cdot 4} : - \frac{9}{2}

The solutions to the quadratic equation are:

a = - \frac{1}{2}, a = - \frac{9}{2}

75 + 2.5 x \leq 195.5

(2 x - 5) (x + 3) = 0

\frac{2 x - 1}{9} \leq \frac{5}{9}

3 r^{2} - 10 r + 8

\frac{1}{6} \leq \frac{2 x - 13}{12} \leq \frac{2}{3}

What are the solutions to the equation 4a^2+20a=-9 ?
The solutions to the equation 4a^2+20a=-9 are a=-1/2 ,a=-9/2
Find the zeros of 4a^2+20a=-9
The zeros of 4a^2+20a=-9 are a=-1/2 ,a=-9/2