What are the solutions to the equation (2x-5)(x+3)=0 ?

The solutions to the equation (2x-5)(x+3)=0 are x= 5/2 ,x=-3

Find the zeros of (2x-5)(x+3)=0

The zeros of (2x-5)(x+3)=0 are x= 5/2 ,x=-3

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(2 x - 5) (x + 3) = 0

x = \frac{5}{2}, x = - 3

Decimal Notation

x = 2.5, x = - 3

Solution steps

(2 x - 5) (x + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x - 5 = 0 or x + 3 = 0

Solve

2 x - 5 = 0 : x = \frac{5}{2}

Solve

x + 3 = 0 : x = - 3

The solutions to the quadratic equation are:

x = \frac{5}{2}, x = - 3

\frac{2 x - 1}{9} \leq \frac{5}{9}

3 r^{2} - 10 r + 8

\frac{1}{6} \leq \frac{2 x - 13}{12} \leq \frac{2}{3}

5 x^{2} - 13 x - 6

∣ 5 x + 4 \geq 8 x - 1

What are the solutions to the equation (2x-5)(x+3)=0 ?
The solutions to the equation (2x-5)(x+3)=0 are x= 5/2 ,x=-3
Find the zeros of (2x-5)(x+3)=0
The zeros of (2x-5)(x+3)=0 are x= 5/2 ,x=-3