What are the solutions to the equation (x^2+x)/7 =8 ?

The solutions to the equation (x^2+x)/7 =8 are x=7,x=-8

Find the zeros of (x^2+x)/7 =8

The zeros of (x^2+x)/7 =8 are x=7,x=-8

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\frac{x ^{2} + x}{7} = 8

x = 7, x = - 8

Solution steps

\frac{x ^{2} + x}{7} = 8

Multiply both sides by

7

x^{2} + x = 56

Move

56

to the left side

x^{2} + x - 56 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 56 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 56) = 15

x_{1, 2} = \frac{- 1 \pm 15}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 15}{2 \cdot 1}, x_{2} = \frac{- 1 - 15}{2 \cdot 1}

x = \frac{- 1 + 15}{2 \cdot 1} : 7

x = \frac{- 1 - 15}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

x = 7, x = - 8

(x - 5) (x + 8) = 0

- 2 s^{5} + 10 s^{3}

4 x^{2} - 25 x - 21

20 a b^{2} - 15 a^{2} b

2 (4)^{2}

What are the solutions to the equation (x^2+x)/7 =8 ?
The solutions to the equation (x^2+x)/7 =8 are x=7,x=-8
Find the zeros of (x^2+x)/7 =8
The zeros of (x^2+x)/7 =8 are x=7,x=-8