What are the solutions to the equation 5y^2+45y=0 ?

The solutions to the equation 5y^2+45y=0 are y=0,y=-9

Find the zeros of 5y^2+45y=0

The zeros of 5y^2+45y=0 are y=0,y=-9

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5 y^{2} + 45 y = 0

y = 0, y = - 9

Solution steps

5 y^{2} + 45 y = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 45 \pm 4 5 ^{2} - 4 \cdot 5 \cdot 0}{2 \cdot 5}

4 5^{2} - 4 \cdot 5 \cdot 0 = 45

y_{1, 2} = \frac{- 45 \pm 45}{2 \cdot 5}

Separate the solutions

y_{1} = \frac{- 45 + 45}{2 \cdot 5}, y_{2} = \frac{- 45 - 45}{2 \cdot 5}

y = \frac{- 45 + 45}{2 \cdot 5} : 0

y = \frac{- 45 - 45}{2 \cdot 5} : - 9

The solutions to the quadratic equation are:

y = 0, y = - 9

6 x - 4 < 2 x or - 2 x \leq - 6

(x - 2) (x + 1) = 4

3 x^{2} - 4 x = - 8

- \frac{7}{8} + \frac{1}{4}

4 x - 2 x^{2} \geq 0

What are the solutions to the equation 5y^2+45y=0 ?
The solutions to the equation 5y^2+45y=0 are y=0,y=-9
Find the zeros of 5y^2+45y=0
The zeros of 5y^2+45y=0 are y=0,y=-9