What is the answer to q+log_{2}(6)=2q+2 ?

The answer to q+log_{2}(6)=2q+2 is q=log_{2}(6)-2

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q+log_{2}(6)=2q+2

q + lo g_{2} (6) = 2 q + 2

q = lo g_{2} (6) - 2

Decimal Notation

q = 0.58496 \dots

Solution steps

q + lo g_{2} (6) = 2 q + 2

Move

lo g_{2} (6)

to the right side

q = 2 q + 2 - lo g_{2} (6)

Move

2 q

to the left side

- q = 2 - lo g_{2} (6)

Divide both sides by

- 1

q = lo g_{2} (6) - 2

- 4 - (- 6)

x - x^{2} = lo g_{5} (\frac{1}{25})

7 x^{2} - 14 x + 5 = - x^{2}

a^{2} + 5 a - 14

\frac{4 x ^{- 2}}{y ^{- 8}}

What is the answer to q+log_{2}(6)=2q+2 ?
The answer to q+log_{2}(6)=2q+2 is q=log_{2}(6)-2
Solve for q: q+log_{2}(6)=2q+2
The solution is q=log_{2}(6)-2