What are the solutions to the equation x^2-3x+8=0 ?

The solutions to the equation x^2-3x+8=0 are x= 3/2+i(sqrt(23))/2 ,x= 3/2-i(sqrt(23))/2

Find the zeros of x^2-3x+8=0

The zeros of x^2-3x+8=0 are x= 3/2+i(sqrt(23))/2 ,x= 3/2-i(sqrt(23))/2

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x^{2} - 3 x + 8 = 0

x = \frac{3}{2} + i \frac{23}{2}, x = \frac{3}{2} - i \frac{23}{2}

Solution steps

x^{2} - 3 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot 8}{2 \cdot 1}

Simplify

(- 3)^{2} - 4 \cdot 1 \cdot 8 : 23 i

x_{1, 2} = \frac{- ( - 3 ) \pm 23 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 23 i}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 23 i}{2 \cdot 1}

x = \frac{- ( - 3 ) + 23 i}{2 \cdot 1} : \frac{3}{2} + i \frac{23}{2}

x = \frac{- ( - 3 ) - 23 i}{2 \cdot 1} : \frac{3}{2} - i \frac{23}{2}

The solutions to the quadratic equation are:

x = \frac{3}{2} + i \frac{23}{2}, x = \frac{3}{2} - i \frac{23}{2}

- \frac{1}{3} (1)

(4 + 2 i) - (7 - 3 i)

∣ x ∣ \geq 3

4 x (2 x + 3) = 36

- 5 g > 25

What are the solutions to the equation x^2-3x+8=0 ?
The solutions to the equation x^2-3x+8=0 are x= 3/2+i(sqrt(23))/2 ,x= 3/2-i(sqrt(23))/2
Find the zeros of x^2-3x+8=0
The zeros of x^2-3x+8=0 are x= 3/2+i(sqrt(23))/2 ,x= 3/2-i(sqrt(23))/2