What are the solutions to the equation 4x(2x+3)=36 ?

The solutions to the equation 4x(2x+3)=36 are x= 3/2 ,x=-3

Find the zeros of 4x(2x+3)=36

The zeros of 4x(2x+3)=36 are x= 3/2 ,x=-3

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4 x (2 x + 3) = 36

x = \frac{3}{2}, x = - 3

Decimal Notation

x = 1.5, x = - 3

Solution steps

4 x (2 x + 3) = 36

Expand

4 x (2 x + 3) : 8 x^{2} + 12 x

8 x^{2} + 12 x = 36

Move

36

to the left side

8 x^{2} + 12 x - 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 8 ( - 36 )}{2 \cdot 8}

1 2^{2} - 4 \cdot 8 (- 36) = 36

x_{1, 2} = \frac{- 12 \pm 36}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 12 + 36}{2 \cdot 8}, x_{2} = \frac{- 12 - 36}{2 \cdot 8}

x = \frac{- 12 + 36}{2 \cdot 8} : \frac{3}{2}

x = \frac{- 12 - 36}{2 \cdot 8} : - 3

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = - 3

- 5 g > 25

∣ 2 x + 3 ∣ < - 5

x^{2} \cdot x^{- 1}

∣ 2 x - 5 ∣ = ∣ x + 3 ∣

9 + n = - 2

What are the solutions to the equation 4x(2x+3)=36 ?
The solutions to the equation 4x(2x+3)=36 are x= 3/2 ,x=-3
Find the zeros of 4x(2x+3)=36
The zeros of 4x(2x+3)=36 are x= 3/2 ,x=-3