What are the solutions to the equation -x^2+6x=0 ?

The solutions to the equation -x^2+6x=0 are x=0,x=6

Find the zeros of -x^2+6x=0

The zeros of -x^2+6x=0 are x=0,x=6

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- x^{2} + 6 x = 0

x = 0, x = 6

Solution steps

- x^{2} + 6 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 1 ) \cdot 0}{2 ( - 1 )}

6^{2} - 4 (- 1) \cdot 0 = 6

x_{1, 2} = \frac{- 6 \pm 6}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 6 + 6}{2 ( - 1 )}, x_{2} = \frac{- 6 - 6}{2 ( - 1 )}

x = \frac{- 6 + 6}{2 ( - 1 )} : 0

x = \frac{- 6 - 6}{2 ( - 1 )} : 6

The solutions to the quadratic equation are:

x = 0, x = 6

- x^{2} - 9 x - 18 > 0

x^{2} + \frac{7}{2} x + \frac{3}{2} = 0

5 x^{2} + 8 x + 2 = 0

36 c^{2} - 121 d^{2}

5 (x - 3) = 4 (x - 6)

What are the solutions to the equation -x^2+6x=0 ?
The solutions to the equation -x^2+6x=0 are x=0,x=6
Find the zeros of -x^2+6x=0
The zeros of -x^2+6x=0 are x=0,x=6