What are the solutions to the equation x^2+7/2 x+3/2 =0 ?

The solutions to the equation x^2+7/2 x+3/2 =0 are x=-1/2 ,x=-3

Find the zeros of x^2+7/2 x+3/2 =0

The zeros of x^2+7/2 x+3/2 =0 are x=-1/2 ,x=-3

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x^{2} + \frac{7}{2} x + \frac{3}{2} = 0

x = - \frac{1}{2}, x = - 3

Decimal Notation

x = - 0.5, x = - 3

Solution steps

x^{2} + \frac{7}{2} x + \frac{3}{2} = 0

Multiply both sides by

2

2 x^{2} + 7 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 2 \cdot 3}{2 \cdot 2}

7^{2} - 4 \cdot 2 \cdot 3 = 5

x_{1, 2} = \frac{- 7 \pm 5}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 7 + 5}{2 \cdot 2}, x_{2} = \frac{- 7 - 5}{2 \cdot 2}

x = \frac{- 7 + 5}{2 \cdot 2} : - \frac{1}{2}

x = \frac{- 7 - 5}{2 \cdot 2} : - 3

The solutions to the quadratic equation are:

x = - \frac{1}{2}, x = - 3

5 x^{2} + 8 x + 2 = 0

36 c^{2} - 121 d^{2}

5 (x - 3) = 4 (x - 6)

6 x^{2} - 19 x + 8

\frac{3 + 2 i}{1 - 4 i}

What are the solutions to the equation x^2+7/2 x+3/2 =0 ?
The solutions to the equation x^2+7/2 x+3/2 =0 are x=-1/2 ,x=-3
Find the zeros of x^2+7/2 x+3/2 =0
The zeros of x^2+7/2 x+3/2 =0 are x=-1/2 ,x=-3