What are the solutions to the equation 10=2x^2-8x ?

The solutions to the equation 10=2x^2-8x are x=5,x=-1

Find the zeros of 10=2x^2-8x

The zeros of 10=2x^2-8x are x=5,x=-1

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10 = 2 x^{2} - 8 x

x = 5, x = - 1

Solution steps

10 = 2 x^{2} - 8 x

Switch sides

2 x^{2} - 8 x = 10

Move

10

to the left side

2 x^{2} - 8 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 2 ( - 10 )}{2 \cdot 2}

(- 8)^{2} - 4 \cdot 2 (- 10) = 12

x_{1, 2} = \frac{- ( - 8 ) \pm 12}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 12}{2 \cdot 2}, x_{2} = \frac{- ( - 8 ) - 12}{2 \cdot 2}

x = \frac{- ( - 8 ) + 12}{2 \cdot 2} : 5

x = \frac{- ( - 8 ) - 12}{2 \cdot 2} : - 1

The solutions to the quadratic equation are:

x = 5, x = - 1

8 - 5 x = 48

- 16 \geq x - 9

∣ - 2 x + 4 ∣ = 8

3 x^{2} - 18 x y + 4 x y - 24 y^{2}

x - 1 + x + x^{1} = 2 (x + 2) + 4

What are the solutions to the equation 10=2x^2-8x ?
The solutions to the equation 10=2x^2-8x are x=5,x=-1
Find the zeros of 10=2x^2-8x
The zeros of 10=2x^2-8x are x=5,x=-1