What is the answer to (1+r)^1=(29471/27408)^1 ?

The answer to (1+r)^1=(29471/27408)^1 is r= 2063/27408

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(1+r)^1=(29471/27408)^1

(1 + r)^{1} = (\frac{29471}{27408})^{1}

r = \frac{2063}{27408}

Solution steps

(1 + r)^{1} = (\frac{29471}{27408})^{1}

Expand

(1 + r)^{1} : 1 + r

Expand

(\frac{29471}{27408})^{1} : \frac{29471}{27408}

1 + r = \frac{29471}{27408}

Move

1

to the right side

r = \frac{2063}{27408}

3 x - 5 = 0

3 x^{2} + x - 3 = 0

a^{2} - 6 a + 9

\frac{4 - x}{x + 1} \geq - 3

2 x + 1 = x + 11

What is the answer to (1+r)^1=(29471/27408)^1 ?
The answer to (1+r)^1=(29471/27408)^1 is r= 2063/27408
Solve for r: (1+r)^1=(29471/27408)^1
The solution is r= 2063/27408