What are the solutions to the equation 3x^2+x-3=0 ?

The solutions to the equation 3x^2+x-3=0 are x=(-1+sqrt(37))/6 ,x=(-1-sqrt(37))/6

Find the zeros of 3x^2+x-3=0

The zeros of 3x^2+x-3=0 are x=(-1+sqrt(37))/6 ,x=(-1-sqrt(37))/6

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3 x^{2} + x - 3 = 0

x = \frac{- 1 + 37}{6}, x = \frac{- 1 - 37}{6}

Solution steps

3 x^{2} + x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 3 ( - 3 )}{2 \cdot 3}

1^{2} - 4 \cdot 3 (- 3) = 37

x_{1, 2} = \frac{- 1 \pm 37}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 1 + 37}{2 \cdot 3}, x_{2} = \frac{- 1 - 37}{2 \cdot 3}

x = \frac{- 1 + 37}{2 \cdot 3} : \frac{- 1 + 37}{6}

x = \frac{- 1 - 37}{2 \cdot 3} : \frac{- 1 - 37}{6}

The solutions to the quadratic equation are:

x = \frac{- 1 + 37}{6}, x = \frac{- 1 - 37}{6}

a^{2} - 6 a + 9

\frac{4 - x}{x + 1} \geq - 3

2 x + 1 = x + 11

49 w^{2} - 25 = 0

(\frac{2}{3})^{3} + 1

What are the solutions to the equation 3x^2+x-3=0 ?
The solutions to the equation 3x^2+x-3=0 are x=(-1+sqrt(37))/6 ,x=(-1-sqrt(37))/6
Find the zeros of 3x^2+x-3=0
The zeros of 3x^2+x-3=0 are x=(-1+sqrt(37))/6 ,x=(-1-sqrt(37))/6