What are the solutions to the equation 8x^2-3=2 ?

The solutions to the equation 8x^2-3=2 are x=(sqrt(5))/(2sqrt(2)),x=-(sqrt(5))/(2sqrt(2))

Find the zeros of 8x^2-3=2

The zeros of 8x^2-3=2 are x=(sqrt(5))/(2sqrt(2)),x=-(sqrt(5))/(2sqrt(2))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

8 x^{2} - 3 = 2

x = \frac{5}{2 2}, x = - \frac{5}{2 2}

Solution steps

8 x^{2} - 3 = 2

Move

3

to the right side

8 x^{2} = 5

Divide both sides by

8

x^{2} = \frac{5}{8}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{5}{8}, x = - \frac{5}{8}

\frac{5}{8} = \frac{5}{2 2}

- \frac{5}{8} = - \frac{5}{2 2}

x = \frac{5}{2 2}, x = - \frac{5}{2 2}

\frac{r}{- 6} + 5 < 7

(3 x + 2)^{2} = 3

3 (0) - 2 y = 6

(\frac{1}{4})^{2} + 5 - (3 (\frac{1}{4} - \frac{2}{7}) + 1)

(k^{3} - 7 k + 2) - (k^{2} - 12)

What are the solutions to the equation 8x^2-3=2 ?
The solutions to the equation 8x^2-3=2 are x=(sqrt(5))/(2sqrt(2)),x=-(sqrt(5))/(2sqrt(2))
Find the zeros of 8x^2-3=2
The zeros of 8x^2-3=2 are x=(sqrt(5))/(2sqrt(2)),x=-(sqrt(5))/(2sqrt(2))