What are the solutions to the equation (3x+2)^2=3 ?

The solutions to the equation (3x+2)^2=3 are x=(sqrt(3)-2)/3 ,x=(-sqrt(3)-2)/3

Find the zeros of (3x+2)^2=3

The zeros of (3x+2)^2=3 are x=(sqrt(3)-2)/3 ,x=(-sqrt(3)-2)/3

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(3 x + 2)^{2} = 3

x = \frac{3 - 2}{3}, x = \frac{- 3 - 2}{3}

Solution steps

(3 x + 2)^{2} = 3

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x + 2 = 3 : x = \frac{3 - 2}{3}

Solve

3 x + 2 = - 3 : x = \frac{- 3 - 2}{3}

The solutions to the quadratic equation are:

x = \frac{3 - 2}{3}, x = \frac{- 3 - 2}{3}

3 (0) - 2 y = 6

(\frac{1}{4})^{2} + 5 - (3 (\frac{1}{4} - \frac{2}{7}) + 1)

(k^{3} - 7 k + 2) - (k^{2} - 12)

∣ x - 4 ∣ > 2

\frac{1 - 8 i}{- 2 + 3 i}

What are the solutions to the equation (3x+2)^2=3 ?
The solutions to the equation (3x+2)^2=3 are x=(sqrt(3)-2)/3 ,x=(-sqrt(3)-2)/3
Find the zeros of (3x+2)^2=3
The zeros of (3x+2)^2=3 are x=(sqrt(3)-2)/3 ,x=(-sqrt(3)-2)/3