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There are 3 consecutive integers. 4 more than the smaller number plus twice the 3rd number is 7 less then the 2nd number. Find the smallest integer of the 3 consecutive integers

Solution

Solution

The smallest number : - 7

Solution steps

Represent the numbers with

x

First number : x

Consecutive number 1 : x + 1

Consecutive number 2 : x + 2

A.T.Q.:

4 + x + 2 (x + 2) = x + 1 - 7

Solve

4 + x + 2 (x + 2) = x + 1 - 7 : x = - 7

x + 1 = - 7 + 1 = - 6

x + 2 = - 7 + 2 = - 5

Select the smallest solution:

- 7

The smallest number : - 7

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