There are 3 consecutive integers. 4 more than the smaller number plus twice the 3rd number is 7 less then the 2nd number. Find the smallest integer of the 3 consecutive integers

解

T h ere a re 3 co n sec u t i v e in t e g ers . 4 m ore t han t h e s ma ll er n u mb er pl u s tw i ce t h e 3 r d n u mb er i s 7 l ess t h e n t h e 2 n d n u mb er . F in d t h e s ma ll es t in t e g er o f t h e 3 co n sec u t i v e in t e g ers

The smallest number : - 7

解答ステップ

Represent the numbers with

x

First number : x

Consecutive number 1 : x + 1

Consecutive number 2 : x + 2

A.T.Q.:

4 + x + 2 (x + 2) = x + 1 - 7

解く

4 + x + 2 (x + 2) = x + 1 - 7 : x = - 7

x + 1 = - 7 + 1 = - 6

x + 2 = - 7 + 2 = - 5

Select the smallest solution:

- 7

The smallest number : - 7