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Two cyclists leave towns 156 kilometers apart at the same time and travel toward each other. One cyclist travels 3kph slower than the other. If they meet in 4 hours, what is the rate of each cyclist?

Solution

Solution

first cyclis t^{'} s speed : 18

second cyclis t^{'} s speed : 21

Solution steps

Translate the problem into an equation:

x \cdot 4 + (x + 3) \cdot 4 = 156

Solve for

x, x \cdot 4 + (x + 3) \cdot 4 = 156 : x = 18

Find speed

first cyclis t^{'} s speed : 18

second cyclis t^{'} s speed : 21

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