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Two small planes start from the same point and fly in opposite directions. The first plane is flying 35 mph slower than the second plane. In 3 h, the planes are 795 mi apart. Find the rate of each plane.

Solution

Solution

first plan e^{'} s speed : 115

second plan e^{'} s speed : 150

Solution steps

Translate the problem into an equation:

x \cdot 3 + (x + 35) \cdot 3 = 795

Solve for

x, x \cdot 3 + (x + 35) \cdot 3 = 795 : x = 115

Find speed

first plan e^{'} s speed : 115

second plan e^{'} s speed : 150

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