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شائع Word Problems >

The sum of 6 consecutive even numbers is 393 .

الحلّ

T h e s u m o f 6 co n sec u t i v e e v e n n u mb ers i s 393 .

الحلّ

The numbers : 60 \frac{1}{2}, 62 \frac{1}{2}, 64 \frac{1}{2}, 66 \frac{1}{2}, 68 \frac{1}{2}, 70 \frac{1}{2}

خطوات الحلّ

Represent the numbers with

x

:

First number : x

Consecutive number 1 : x + 2

Consecutive number 2 : x + 4

Consecutive number 3 : x + 6

Consecutive number 4 : x + 8

Consecutive number 5 : x + 10

A.T.Q.:

x + x + 2 + x + 4 + x + 6 + x + 8 + x + 10 = 393

x + x + 2 + x + 4 + x + 6 + x + 8 + x + 10 = 393

حلّ:

x = \frac{121}{2}

x + 2 = \frac{121}{2} + 2 = \frac{125}{2}

x + 4 = \frac{121}{2} + 4 = \frac{129}{2}

x + 6 = \frac{121}{2} + 6 = \frac{133}{2}

x + 8 = \frac{121}{2} + 8 = \frac{137}{2}

x + 10 = \frac{121}{2} + 10 = \frac{141}{2}

حوّل من كسر تخيّليّ لعدد مختلط:

\frac{121}{2} = 60 \frac{1}{2}

حوّل من كسر تخيّليّ لعدد مختلط:

\frac{125}{2} = 62 \frac{1}{2}

حوّل من كسر تخيّليّ لعدد مختلط:

\frac{129}{2} = 64 \frac{1}{2}

حوّل من كسر تخيّليّ لعدد مختلط:

\frac{133}{2} = 66 \frac{1}{2}

حوّل من كسر تخيّليّ لعدد مختلط:

\frac{137}{2} = 68 \frac{1}{2}

حوّل من كسر تخيّليّ لعدد مختلط:

\frac{141}{2} = 70 \frac{1}{2}

The numbers : 60 \frac{1}{2}, 62 \frac{1}{2}, 64 \frac{1}{2}, 66 \frac{1}{2}, 68 \frac{1}{2}, 70 \frac{1}{2}

أمثلة شائعة

1 less than the product of 5 and a number.four times the sum of a number and 15 is greater than or equal to-20 what number is 3% of 148 The sum of three consecutive integers is 120. find the numbers.the difference between two thirds of a number and one sixth of the same number is seventy five what is the number