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Two cyclists start at the same point and travel in opposite directions. One cyclist travels 4 miles per hour slower than the other. If the two cyclists are 60 miles apart after 2 hours, what is the rate of each cyclists?

Solution

Solution

first cyclis t^{'} s speed : 13

second cyclis t^{'} s speed : 17

Solution steps

Translate the problem into an equation:

x \cdot 2 + (x + 4) \cdot 2 = 60

Solve for

x, x \cdot 2 + (x + 4) \cdot 2 = 60 : x = 13

Find speed

first cyclis t^{'} s speed : 13

second cyclis t^{'} s speed : 17

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