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The sum of two numbers is 48. If one number is three more than twice the second number, which of the following is the smaller number?

Solution

The sum of two numbers is 48. If one number is three more than twice the second number, which of the following is the smaller number?

Solution

The numbers : 48 - \frac{97 - 9049}{4}, \frac{97 - 9049}{4} or 48 - \frac{97 + 9049}{4}, \frac{97 + 9049}{4}

Solution steps

Represent the numbers with

x and y

:

number 1 : x

number 2 : y

A.T.Q.:

x + y = 48

x = 3 + 2 y x

x + y = 48, x = 3 + 2 y x : (x = 48 - \frac{97 - 9049}{4}, y = \frac{97 - 9049}{4} x = 48 - \frac{97 + 9049}{4}, y = \frac{97 + 9049}{4})

The numbers : 48 - \frac{97 - 9049}{4}, \frac{97 - 9049}{4} or 48 - \frac{97 + 9049}{4}, \frac{97 + 9049}{4}

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