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for the set of three consecutive odd integers, three times the largest integer is 7 less than twice the sum of the other two integers. what is the largest integer in the set?

Solution

Solution

No Solution

Solution steps

Represent the numbers with

x

First number : x

Consecutive number 1 : x + 2

Consecutive number 2 : x + 4

A.T.Q.:

3 (x + 4) = 2 \cdot 7 - 2 (x + x + 2 + x + 4) - 7

Solve

3 (x + 4) = 2 \cdot 7 - 2 (x + x + 2 + x + 4) - 7 : x = - \frac{17}{9}

x + 2 = - \frac{17}{9} + 2 = \frac{1}{9}

x + 4 = - \frac{17}{9} + 4 = \frac{19}{9}

Even value

\frac{1}{9}

discarded

No Solution

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