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The sum of an integer and 5 times the next consecutive odd integer is 29. Find the value of the lesser integer.

Solution

The sum of an integer and 5 times the next consecutive odd integer is 29. Find the value of the lesser integer.

Solution

The smallest number : 3 \frac{1}{6}

Solution steps

Represent the numbers with

x

:

First number : x

Consecutive number : x + 2

A.T.Q.:

x + 5 (x + 2) = 29

Solve

x + 5 (x + 2) = 29 : x = \frac{19}{6}

x + 2 = \frac{19}{6} + 2 = \frac{31}{6}

Convert improper fractions to mixed numbers:

\frac{19}{6} = 3 \frac{1}{6}

Convert improper fractions to mixed numbers:

\frac{31}{6} = 5 \frac{1}{6}

Select the smallest solution:

3 \frac{1}{6}

The smallest number : 3 \frac{1}{6}

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