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Popular >

Find three consecutive integers such that 16 more than half of the larger number is two thirds of the smallest number.

Solution

Find three consecutive integers such that 16 more than half of the larger number is two thirds of the smallest number.

Solution

The numbers : 102, 103, 104

Solution steps

Represent the numbers with

x

:

First number : x

Consecutive number 1 : x + 1

Consecutive number 2 : x + 2

A.T.Q.:

16 + \frac{1}{2} (x + 2) = \frac{2}{3} x

Solve

16 + \frac{1}{2} (x + 2) = \frac{2}{3} x : x = 102

x + 1 = 102 + 1 = 103

x + 2 = 102 + 2 = 104

The numbers : 102, 103, 104

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