Nelly and Pearl are playing around with a pair of 6-sided dice. Nelly rolls one of the dice, and Pearl rolls the other.What is the probability that they will both roll a 1?

Solution

Solution

\frac{1}{36}

Solution steps

The possible outcomes when two dice are rolled are

6 \cdot 6

Therefore, the number of possible outcomes:

6^{2}

Find the number of favorable outcomes of they will both roll a 1:

1

Probability

= \frac{number of favorable outcomes}{total number of outcomes}

= \frac{1}{6 ^{2}}

6^{2} = 36

= \frac{1}{36}

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