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What is the probability of getting exactly two heads when tossing a 10 peso coin three times?

Solution

What is the probability of getting exactly two heads when tossing a 10 peso coin three times?

Solution

\frac{3}{8}

Solution steps

The possible outcomes when a coin is thrown three times are

2 \cdot 2 \cdot 2

Therefore, the number of possible outcomes:

2^{3}

Find the number of favorable outcomes of getting exactly 2 heads when tossing a 10 peso coin 3 times:

3

Probability

= \frac{number of favorable outcomes}{total number of outcomes}

= \frac{3}{2 ^{3}}

2^{3} = 8

= \frac{3}{8}

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