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The sum of 5 consecutive integers is 110 .What is the fourth number in this sequence?

Solution

The sum of 5 consecutive integers is 110 .What is the fourth number in this sequence?

Solution

The number : 23

Solution steps

Represent the numbers with

x

:

First number : x

Consecutive number 1 : x + 1

Consecutive number 2 : x + 2

Consecutive number 3 : x + 3

Consecutive number 4 : x + 4

A.T.Q.:

x + x + 1 + x + 2 + x + 3 + x + 4 = 110

Solve

x + x + 1 + x + 2 + x + 3 + x + 4 = 110 : x = 20

x + 1 = 20 + 1 = 21

x + 2 = 20 + 2 = 22

x + 3 = 20 + 3 = 23

x + 4 = 20 + 4 = 24

The number : 23

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