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Two consecutive positive numbers are such that the sum of their squares is 113. Find the two numbers

Solution

Two consecutive positive numbers are such that the sum of their squares is 113. Find the two numbers

Solution

The numbers : 7, 8

Solution steps

Represent the numbers with

x

:

First number : x

Consecutive number : x + 1

A.T.Q.:

x^{2} + (x + 1)^{2} = 113

Solve

x^{2} + (x + 1)^{2} = 113 : x = 7, x = - 8

Select positive solutions:

7

x + 1 = 7 + 1 = 8

The numbers : 7, 8

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