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If a fair die is rolled 3 times, what is the probability, to the nearest thousandth, of getting exactly 2 threes?

Solution

If a fair die is rolled 3 times, what is the probability, to the nearest thousandth, of getting exactly 2 threes?

Solution

\frac{5}{72}

Solution steps

The possible outcomes when three dice are rolled are

6 \cdot 6 \cdot 6

Therefore, the number of possible outcomes:

6^{3}

Find the number of favorable outcomes of to the nearest thousandth of getting exactly 2 threes:

15

Probability

= \frac{number of favorable outcomes}{total number of outcomes}

= \frac{15}{6 ^{3}}

\frac{15}{6 ^{3}} = \frac{5}{72}

= \frac{5}{72}

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