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Two cyclists start at the same point and travel in opposite directions. One cyclist travels 6 kmh slower than the other. If the two cyclists are 150 kilometers apart after 3 hours, what is the rate of each cyclist?

Solution

Solution

first cyclis t^{'} s speed : 22

second cyclis t^{'} s speed : 28

Solution steps

Translate the problem into an equation:

x \cdot 3 + (x + 6) \cdot 3 = 150

Solve for

x, x \cdot 3 + (x + 6) \cdot 3 = 150 : x = 22

Find speed

first cyclis t^{'} s speed : 22

second cyclis t^{'} s speed : 28

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