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Popular >

Find two consecutive positive integers such that the square of the larger integer is nineteen more than nine times the smaller integer.

Solution

Find two consecutive positive integers such that the square of the larger integer is nineteen more than nine times the smaller integer.

Solution

The numbers : 9, 10

Solution steps

Represent the numbers with

x

:

First number : x

Consecutive number : x + 1

A.T.Q.:

(x + 1)^{2} = 19 + 9 x

Solve

(x + 1)^{2} = 19 + 9 x : x = 9, x = - 2

Select positive solutions:

9

x + 1 = 9 + 1 = 10

The numbers : 9, 10

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