Find three consecutive odd integers such that three times the product of the first and last integers, decreased by 150, is equal to the square of the second integer.

Solution

Solution

Aucune solution

étapes des solutions

Represent the numbers with

x

First number : x

Consecutive number 1 : x + 2

Consecutive number 2 : x + 4

A.T.Q.:

3 \dots - 150 = (x + 2)^{2}

Résoudre

3 \dots - 150 = (x + 2)^{2} : x = 3 \dots - 150 - 2, x = - 3 \dots - 150 - 2

Insérer

x = 3 \dots - 150 - 2 :

Non valide

Insérer

x = - 3 \dots - 150 - 2 :

Non valide

Aucune solution

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