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Popular >

The sum of the squares of three consecutive integers is 110. Find the numbers

Solution

The sum of the squares of three consecutive integers is 110. Find the numbers

Solution

The numbers : 5, 6, 7 or - 7, - 6, - 5

Solution steps

Represent the numbers with

x

:

First number : x

Consecutive number 1 : x + 1

Consecutive number 2 : x + 2

A.T.Q.:

x^{2} + (x + 1)^{2} + (x + 2)^{2} = 110

Solve

x^{2} + (x + 1)^{2} + (x + 2)^{2} = 110 : x = 5, x = - 7

Plug in

x = 5 : 6, 7

Plug in

x = - 7 : - 6, - 5

The numbers : 5, 6, 7 or - 7, - 6, - 5

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