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Two cyclists leave towns 112 kilometers apart at the same time and travel toward each other. One cyclist travels 4 kph faster than the other. If they meet in 2 hours, what is the rate of each cyclist?

Solution

Solution

first cyclis t^{'} s speed : 30

second cyclis t^{'} s speed : 26

Solution steps

Translate the problem into an equation:

x \cdot 2 + (x - 4) \cdot 2 = 112

Solve for

x, x \cdot 2 + (x - 4) \cdot 2 = 112 : x = 30

Find speed

first cyclis t^{'} s speed : 30

second cyclis t^{'} s speed : 26

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