find 2 positive consecutive odd integers such that the square of the smaller increased by twice the larger is 103

解

f in d 2 p os i t i v e co n sec u t i v e o dd in t e g ers s u c h t ha t t h e s q u a re o f t h e s ma ll er in cre a se d b y tw i ce t h e l a r g er i s 103

The number : - \frac{1 + 3 23}{2}

解答ステップ

Represent the number with

x

A.T.Q.:

2 x^{2} + 2 x = 103

x

を解く

2 x^{2} + 2 x = 103 : x = \frac{- 1 + 3 23}{2}, x = - \frac{1 + 3 23}{2}

挿入

x = \frac{- 1 + 3 23}{2} :

無効

The number : - \frac{1 + 3 23}{2}