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Popular >

find 2 positive consecutive odd integers such that the square of the smaller increased by twice the larger is 103

Solution

find 2 positive consecutive odd integers such that the square of the smaller increased by twice the larger is 103

Solution

The number : - \frac{1 + 3 23}{2}

Solution steps

Represent the number with

x

A.T.Q.:

2 x^{2} + 2 x = 103

Solve for

x, 2 x^{2} + 2 x = 103 : x = \frac{- 1 + 3 23}{2}, x = - \frac{1 + 3 23}{2}

Plug in

x = \frac{- 1 + 3 23}{2} :

Invalid

The number : - \frac{1 + 3 23}{2}

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