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人気のある Word Problems >

One number is five more than twice another. If their sum is decreased by ten, the result is 5

解

O n e n u mb er i s f i v e m ore t han tw i ce an o t h er . I f t h e i r s u m i s d ecre a se d b y t e n, t h e res u lt i s 5

解

The numbers : 11 \frac{2}{3}, 3 \frac{1}{3}

解答ステップ

Represent the numbers with

x and y

:

number 1 : x

number 2 : y

A.T.Q.:

x = 5 + 2 y

x + y - 10 = 5

x = 5 + 2 y, x + y - 10 = 5 : x = \frac{35}{3}, y = \frac{10}{3}

仮分数を帯分数に変換する:

\frac{35}{3} = 11 \frac{2}{3}

仮分数を帯分数に変換する:

\frac{10}{3} = 3 \frac{1}{3}

The numbers : 11 \frac{2}{3}, 3 \frac{1}{3}

人気の例

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