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What is the volume of a sphere with a radius of 41 in, rounded to the nearest tenth of a cubic inch?

Solution

What is the volume of a sphere with a radius of 41 in, rounded to the nearest tenth of a cubic inch?

Solution

v o l u m e : \frac{275684 π}{3} i n^{3}

+1

Decimal Notation

288695.60970 \dots

Solution steps

Given:

r a d i u s : 41 in

Sphere Volume:

V = \frac{275684 π}{3}

v o l u m e : \frac{275684 π}{3} i n^{3}

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