Six years ago a father was twelve times as old as his son. In three years time the father will be three times as old as his son. How old are they now?

Solution

Solution

Father^{'} s age is : 30

Boy^{'} s age is : 8

Solution steps

Translate the problem into an equation:

x - 6 = 12 (y - 6), x + 3 = 3 (y + 3)

x - 6 = 12 (y - 6), x + 3 = 3 (y + 3) : x = 30, y = 8

Father^{'} s age is : 30

Boy^{'} s age is : 8

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