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Popular >

the difference of two numbers is equal to 6. moreover, the square of the sum of these numbers is 441. find these numbers

Solution

the difference of two numbers is equal to 6. moreover, the square of the sum of these numbers is 441. find these numbers

Solution

The numbers : 441 - \frac{441 - 6}{2}, \frac{441 - 6}{2} or 441 - \frac{441 + 6}{2}, \frac{441 + 6}{2}

Solution steps

Represent the numbers with

x and y

:

number 1 : x

number 2 : y

A.T.Q.:

(x - y)^{2} = 6

x + y = 441

Solve the system of equations:

(x - y)^{2} = 6, x + y = 441 : (x = 441 - \frac{441 - 6}{2}, x = 441 - \frac{441 + 6}{2}, y = \frac{441 - 6}{2} y = \frac{441 + 6}{2})

The numbers : 441 - \frac{441 - 6}{2}, \frac{441 - 6}{2} or 441 - \frac{441 + 6}{2}, \frac{441 + 6}{2}

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