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Popular >

find 3 positive consecutive integers such that the product of the second integer and the third integer is 72.

Solution

find 3 positive consecutive integers such that the product of the second integer and the third integer is 72.

Solution

The numbers : 7, 8, 9

Solution steps

Represent the numbers with

x

:

First number : x

Consecutive number 1 : x + 1

Consecutive number 2 : x + 2

A.T.Q.:

(x + 1) (x + 2) = 72

Solve

(x + 1) (x + 2) = 72 : x = 7, x = - 10

Select positive solutions:

7

x + 1 = 7 + 1 = 8

x + 2 = 7 + 2 = 9

The numbers : 7, 8, 9

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