arcsinh(1)

Lösung

arcsinh (1)

ln (1 + 2)

Dezimale

0.88137 \dots

Schritte zur Lösung

arcsinh (1)

Hyperbolische Identität anwenden:

arcsinh (x) = ln (x + x^{2} + 1)

= ln (1 + 1^{2} + 1)

Vereinfache

= ln (1 + 2)

tan (\frac{π}{4})

sin^{2} (x) = \frac{1}{4}, 0 \leq x \leq 2 π

tan (\frac{7 π}{6})

tan^{2} (x) - 1 = 0

cos (2 θ) = - \frac{3}{2}