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受欢迎的三角函数 >

solvefor y,d^2-4d+4y=e^2x+x^2+x+sin^2(x)

解答

求解

y, d^{2} - 4 d + 4 y = e^{2} x + x^{2} + x + sin^{2} (x)

解答

y = \frac{e ^{2} x + x ^{2} + x + sin ^{2} ( x ) - d ^{2} + 4 d}{4}

求解步骤

d^{2} - 4 d + 4 y = e^{2} x + x^{2} + x + sin^{2} (x)

将

d^{2}

到右边

d^{2} - 4 d + 4 y = e^{2} x + x^{2} + x + sin^{2} (x)

两边减去

d^{2}

d^{2} - 4 d + 4 y - d^{2} = e^{2} x + x^{2} + x + sin^{2} (x) - d^{2}

化简

- 4 d + 4 y = e^{2} x + x^{2} + x + sin^{2} (x) - d^{2}

- 4 d + 4 y = e^{2} x + x^{2} + x + sin^{2} (x) - d^{2}

将

4 d

到右边

- 4 d + 4 y = e^{2} x + x^{2} + x + sin^{2} (x) - d^{2}

两边加上

4 d

- 4 d + 4 y + 4 d = e^{2} x + x^{2} + x + sin^{2} (x) - d^{2} + 4 d

化简

4 y = e^{2} x + x^{2} + x + sin^{2} (x) - d^{2} + 4 d

4 y = e^{2} x + x^{2} + x + sin^{2} (x) - d^{2} + 4 d

两边除以

4

4 y = e^{2} x + x^{2} + x + sin^{2} (x) - d^{2} + 4 d

两边除以

4

\frac{4 y}{4} = \frac{e ^{2} x}{4} + \frac{x ^{2}}{4} + \frac{x}{4} + \frac{sin ^{2} ( x )}{4} - \frac{d ^{2}}{4} + \frac{4 d}{4}

化简

\frac{4 y}{4} = \frac{e ^{2} x}{4} + \frac{x ^{2}}{4} + \frac{x}{4} + \frac{sin ^{2} ( x )}{4} - \frac{d ^{2}}{4} + \frac{4 d}{4}

化简

\frac{4 y}{4} : y

\frac{4 y}{4}

数字相除:

\frac{4}{4} = 1

= y

化简

\frac{e ^{2} x}{4} + \frac{x ^{2}}{4} + \frac{x}{4} + \frac{sin ^{2} ( x )}{4} - \frac{d ^{2}}{4} + \frac{4 d}{4} : \frac{e ^{2} x + x ^{2} + x + sin ^{2} ( x ) - d ^{2} + 4 d}{4}

\frac{e ^{2} x}{4} + \frac{x ^{2}}{4} + \frac{x}{4} + \frac{sin ^{2} ( x )}{4} - \frac{d ^{2}}{4} + \frac{4 d}{4}

使用法则

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{e ^{2} x + x ^{2} + x + sin ^{2} ( x ) - d ^{2} + 4 d}{4}

y = \frac{e ^{2} x + x ^{2} + x + sin ^{2} ( x ) - d ^{2} + 4 d}{4}

y = \frac{e ^{2} x + x ^{2} + x + sin ^{2} ( x ) - d ^{2} + 4 d}{4}

y = \frac{e ^{2} x + x ^{2} + x + sin ^{2} ( x ) - d ^{2} + 4 d}{4}

作图

流行的例子

solvefor y,(d^2-5d+6)*y=x+sin^3(x)

so l v e f or y, (d^{2} - 5 d + 6) \cdot y = x + sin^{3} (x)

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so l v e f or t, cot (x) sin^{2} (x) = 1 + cos^{2} (x)

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