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人気のある三角関数 >

solvefor k,sqrt(x^2+y^2)=k*arctan(y/x)

解

解く

k, x^{2} + y^{2} = k \cdot arctan (\frac{y}{x})

解

k = \frac{x ^{2} + y ^{2}}{arctan ( \frac{y}{x} )}; arctan (\frac{y}{x}) \neq = 0

解答ステップ

x^{2} + y^{2} = k arctan (\frac{y}{x})

辺を交換する

k arctan (\frac{y}{x}) = x^{2} + y^{2}

以下で両辺を割る

arctan (\frac{y}{x}); arctan (\frac{y}{x}) \neq = 0

k arctan (\frac{y}{x}) = x^{2} + y^{2}

以下で両辺を割る

arctan (\frac{y}{x}); arctan (\frac{y}{x}) \neq = 0

\frac{k arctan ( \frac{y}{x} )}{arctan ( \frac{y}{x} )} = \frac{x ^{2} + y ^{2}}{arctan ( \frac{y}{x} )}; arctan (\frac{y}{x}) \neq = 0

簡素化

k = \frac{x ^{2} + y ^{2}}{arctan ( \frac{y}{x} )}; arctan (\frac{y}{x}) \neq = 0

k = \frac{x ^{2} + y ^{2}}{arctan ( \frac{y}{x} )}; arctan (\frac{y}{x}) \neq = 0

グラフ

人気の例

solvefor t,cot(90^0+x)=tan(x)

so l v e f or t, cot (9 0^{0} + x) = tan (x)

solvefor t,arccos(((5cos(x)+3))/((5+3cos(x))))=2arctan(1/2*tan(x/2))

so l v e f or t, arccos (\frac{( 5 cos ( x ) + 3 )}{( 5 + 3 cos ( x ) )}) = 2 arctan (\frac{1}{2} \cdot tan (\frac{x}{2}))

solvefor x,y=cos(y/(1.75))+x-0.5y^2

so l v e f or x, y = cos (\frac{y}{1.75}) + x - 0.5 y^{2}

solvefor c,2sin^3(x)+cos^2(x)-cos(x)=0

so l v e f or c, 2 sin^{3} (x) + cos^{2} (x) - cos (x) = 0

solvefor i,sin(x^2)+cos^2(x)+sin(x)+1=0

so l v e f or i, sin (x^{2}) + cos^{2} (x) + sin (x) + 1 = 0