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人気のある三角関数 >

solvefor y,arccos(y/2)=5log_{10}(x/5)

解

解く

y, arccos (\frac{y}{2}) = 5 lo g_{10} (\frac{x}{5})

解

y = 2 cos (5 lo g_{10} (\frac{x}{5}))

解答ステップ

arccos (\frac{y}{2}) = 5 lo g_{10} (\frac{x}{5})

三角関数の逆数プロパティを適用する

arccos (\frac{y}{2}) = 5 lo g_{10} (\frac{x}{5})

arccos (x) = a \Rightarrow x = cos (a)

\frac{y}{2} = cos (5 lo g_{10} (\frac{x}{5}))

\frac{y}{2} = cos (5 lo g_{10} (\frac{x}{5}))

解く

\frac{y}{2} = cos (5 lo g_{10} (\frac{x}{5})) : y = 2 cos (5 lo g_{10} (\frac{x}{5}))

\frac{y}{2} = cos (5 lo g_{10} (\frac{x}{5}))

以下で両辺を乗じる:

2

\frac{y}{2} = cos (5 lo g_{10} (\frac{x}{5}))

以下で両辺を乗じる:

2

\frac{2 y}{2} = 2 cos (5 lo g_{10} (\frac{x}{5}))

簡素化

y = 2 cos (5 lo g_{10} (\frac{x}{5}))

y = 2 cos (5 lo g_{10} (\frac{x}{5}))

y = 2 cos (5 lo g_{10} (\frac{x}{5}))

グラフ

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