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受欢迎的三角函数 >

cot((-x+3n)/4)=0

解答

cot (\frac{- x + 3 n}{4}) = 0

解答

x = - 2 π - 4 πk + 3 n

求解步骤

cot (\frac{- x + 3 n}{4}) = 0

cot (\frac{- x + 3 n}{4}) = 0

的通解

cot (x)

周期表（周期为

πn

）：

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cot (x) \mp \infty 31 \frac{3}{3} 0 - \frac{3}{3} - 1 - 3

\frac{- x + 3 n}{4} = \frac{π}{2} + πn

\frac{- x + 3 n}{4} = \frac{π}{2} + πn

解

\frac{- x + 3 n}{4} = \frac{π}{2} + πk : x = - 2 π - 4 πk + 3 n

\frac{- x + 3 n}{4} = \frac{π}{2} + πk

在两边乘以

4

\frac{- x + 3 n}{4} = \frac{π}{2} + πk

在两边乘以

4

\frac{4 ( - x + 3 n )}{4} = 4 \cdot \frac{π}{2} + 4 πk

化简

\frac{4 ( - x + 3 n )}{4} = 4 \cdot \frac{π}{2} + 4 πk

化简

\frac{4 ( - x + 3 n )}{4} : - x + 3 n

\frac{4 ( - x + 3 n )}{4}

数字相除:

\frac{4}{4} = 1

= - x + 3 n

化简

4 \cdot \frac{π}{2} + 4 πk : 2 π + 4 πk

4 \cdot \frac{π}{2} + 4 πk

4 \cdot \frac{π}{2} = 2 π

4 \cdot \frac{π}{2}

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{π 4}{2}

数字相除:

\frac{4}{2} = 2

= 2 π

= 2 π + 4 πk

- x + 3 n = 2 π + 4 πk

- x + 3 n = 2 π + 4 πk

- x + 3 n = 2 π + 4 πk

将

3 n

到右边

- x + 3 n = 2 π + 4 πk

两边减去

3 n

- x + 3 n - 3 n = 2 π + 4 πk - 3 n

化简

- x = 2 π + 4 πk - 3 n

- x = 2 π + 4 πk - 3 n

两边除以

- 1

- x = 2 π + 4 πk - 3 n

两边除以

- 1

\frac{- x}{- 1} = \frac{2 π}{- 1} + \frac{4 πk}{- 1} - \frac{3 n}{- 1}

化简

\frac{- x}{- 1} = \frac{2 π}{- 1} + \frac{4 πk}{- 1} - \frac{3 n}{- 1}

化简

\frac{- x}{- 1} : x

\frac{- x}{- 1}

使用分式法则:

\frac{- a}{- b} = \frac{a}{b}

= \frac{x}{1}

使用法则

\frac{a}{1} = a

= x

化简

\frac{2 π}{- 1} + \frac{4 πk}{- 1} - \frac{3 n}{- 1} : - 2 π - 4 πk + 3 n

\frac{2 π}{- 1} + \frac{4 πk}{- 1} - \frac{3 n}{- 1}

\frac{2 π}{- 1} = - 2 π

\frac{2 π}{- 1}

使用分式法则:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{2 π}{1}

使用法则

\frac{a}{1} = a

= - 2 π

= - 2 π + \frac{4 πk}{- 1} - \frac{3 n}{- 1}

\frac{4 πk}{- 1} = - 4 πk

\frac{4 πk}{- 1}

使用分式法则:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{4 πk}{1}

使用法则

\frac{a}{1} = a

= - 4 πk

= - 2 π - 4 πk - \frac{3 n}{- 1}

\frac{3 n}{- 1} = - 3 n

\frac{3 n}{- 1}

使用分式法则:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{3 n}{1}

使用法则

\frac{a}{1} = a

= - 3 n

= - 2 π - 4 πk - (- 3 n)

使用法则

- (- a) = a

= - 2 π - 4 πk + 3 n

x = - 2 π - 4 πk + 3 n

x = - 2 π - 4 πk + 3 n

x = - 2 π - 4 πk + 3 n

x = - 2 π - 4 πk + 3 n

作图

流行的例子

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\frac{cos ( a )}{1 + sin ( a )} = sec (a)

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