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受欢迎的三角函数 >

(sin(42))/(22)=(sin(B))/(12)

解答

\frac{sin ( 4 2 ^{\circ} )}{22} = \frac{sin ( B )}{12}

解答

B = 0.37361 \dots + 36 0^{\circ} n, B = 18 0^{\circ} - 0.37361 \dots + 36 0^{\circ} n

+1

弧度

B = 0.37361 \dots + 2 πn, B = π - 0.37361 \dots + 2 πn

求解步骤

\frac{sin ( 4 2 ^{\circ} )}{22} = \frac{sin ( B )}{12}

交换两边

\frac{sin ( B )}{12} = \frac{sin ( 4 2 ^{\circ} )}{22}

在两边乘以

12

\frac{sin ( B )}{12} = \frac{sin ( 4 2 ^{\circ} )}{22}

在两边乘以

12

\frac{12 sin ( B )}{12} = \frac{12 sin ( 4 2 ^{\circ} )}{22}

化简

sin (B) = \frac{6 sin ( 4 2 ^{\circ} )}{11}

sin (B) = \frac{6 sin ( 4 2 ^{\circ} )}{11}

使用反三角函数性质

sin (B) = \frac{6 sin ( 4 2 ^{\circ} )}{11}

sin (B) = \frac{6 sin ( 4 2 ^{\circ} )}{11}

的通解

sin (x) = a \Rightarrow x = arcsin (a) + 36 0^{\circ} n, x = 18 0^{\circ} - arcsin (a) + 36 0^{\circ} n

B = arcsin (\frac{6 sin ( 4 2 ^{\circ} )}{11}) + 36 0^{\circ} n, B = 18 0^{\circ} - arcsin (\frac{6 sin ( 4 2 ^{\circ} )}{11}) + 36 0^{\circ} n

B = arcsin (\frac{6 sin ( 4 2 ^{\circ} )}{11}) + 36 0^{\circ} n, B = 18 0^{\circ} - arcsin (\frac{6 sin ( 4 2 ^{\circ} )}{11}) + 36 0^{\circ} n

以小数形式表示解

B = 0.37361 \dots + 36 0^{\circ} n, B = 18 0^{\circ} - 0.37361 \dots + 36 0^{\circ} n

作图

流行的例子

sin (θ) = \frac{16}{14}

tan (θ) = \frac{83}{47}

solvefor x,2sin(x)-cos(x)sin(x)=0

so l v e f or x, 2 sin (x) - cos (x) sin (x) = 0

5 = 5 sin (4 θ)

cos(x)=(cos(x))/(csc(x))

cos (x) = \frac{cos ( x )}{csc ( x )}