What is the general solution for sin(x)=-1/2 ,(0,2pi) ?

The general solution for sin(x)=-1/2 ,(0,2pi) is x=(7pi)/6 ,x=(11pi)/6

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sin(x)=-1/2 ,(0,2pi)

sin (x) = - \frac{1}{2}, (0, 2 π)

x = \frac{7 π}{6}, x = \frac{11 π}{6}

Degrees

x = 21 0^{\circ}, x = 33 0^{\circ}

Solution steps

sin (x) = - \frac{1}{2}, (0, 2 π)

General solutions for

sin (x) = - \frac{1}{2}

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

x = \frac{7 π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

x = \frac{7 π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

Solutions for the range

(0, 2 π)

x = \frac{7 π}{6}, x = \frac{11 π}{6}

tan (θ) = \frac{4}{3}, cos (θ) < 0

cot (x) = \frac{sin ( x )}{cos ( x )}

0.6 = \frac{cosh ( 0.2 m )}{cosh ( 0.4 m )}

12 cos (2 x) + 5 sin (x) - 9 = 0

sin (x) = \frac{4}{8}

What is the general solution for sin(x)=-1/2 ,(0,2pi) ?
The general solution for sin(x)=-1/2 ,(0,2pi) is x=(7pi)/6 ,x=(11pi)/6