What is the general solution for tan(2x)=+8/15 ?

The general solution for tan(2x)=+8/15 is x=(0.48995…)/2+(pin)/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tan(2x)=+8/15

tan (2 x) = + \frac{8}{15}

x = \frac{0.48995 \dots}{2} + \frac{πn}{2}

Degrees

x = 14.03624 \dots^{\circ} + 9 0^{\circ} n

Solution steps

tan (2 x) = \frac{8}{15}

Apply trig inverse properties

tan (2 x) = \frac{8}{15}

General solutions for

tan (2 x) = + \frac{8}{15}

tan (x) = a \Rightarrow x = arctan (a) + πn

2 x = arctan (\frac{8}{15}) + πn

2 x = arctan (\frac{8}{15}) + πn

Solve

2 x = arctan (\frac{8}{15}) + πn : x = \frac{arctan ( \frac{8}{15} )}{2} + \frac{πn}{2}

2 x = arctan (\frac{8}{15}) + πn

Divide both sides by

2

2 x = arctan (\frac{8}{15}) + πn

Divide both sides by

2

\frac{2 x}{2} = \frac{arctan ( \frac{8}{15} )}{2} + \frac{πn}{2}

Simplify

x = \frac{arctan ( \frac{8}{15} )}{2} + \frac{πn}{2}

x = \frac{arctan ( \frac{8}{15} )}{2} + \frac{πn}{2}

x = \frac{arctan ( \frac{8}{15} )}{2} + \frac{πn}{2}

Show solutions in decimal form

x = \frac{0.48995 \dots}{2} + \frac{πn}{2}

sin (θ) = \frac{7}{25}, cos (\frac{θ}{2}), 0^{\circ} < θ < 9 0^{\circ}

sin (2 x) = - \frac{1}{4}

2 cos^{4} (θ) - 3 cos^{2} (θ) + 1 = 0

2 cos^{2} (θ) + 7 cos (θ) - 4 = 0

sec^{4} (x) = sec^{2} (x) tan^{2} (x) - 2 tan^{4} (x)

What is the general solution for tan(2x)=+8/15 ?
The general solution for tan(2x)=+8/15 is x=(0.48995…)/2+(pin)/2