What is the general solution for sin(θ)= 4/5 ,cos(θ)= 3/5 ?

The general solution for sin(θ)= 4/5 ,cos(θ)= 3/5 is No Solution for θ\in\mathbb{R}

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sin(θ)= 4/5 ,cos(θ)= 3/5

sin (θ) = \frac{4}{5}, cos (θ) = \frac{3}{5}

No Solution for θ \in R

Solution steps

sin (θ) = \frac{4}{5}, cos (θ) = \frac{3}{5}

Apply trig inverse properties

sin (θ) = \frac{4}{5}

General solutions for

sin (θ) = \frac{4}{5}

sin (x) = a \Rightarrow x = arcsin (a) + 2 πn, x = π - arcsin (a) + 2 πn

θ = arcsin (\frac{4}{5}) + 2 πn, θ = π - arcsin (\frac{4}{5}) + 2 πn

θ = arcsin (\frac{4}{5}) + 2 πn, θ = π - arcsin (\frac{4}{5}) + 2 πn

Solutions for the range

cos (θ) = \frac{3}{5}

No Solution for θ \in R

sec (2 x) + tan (2 x) = 8

cos (θ) = \frac{1}{12}

sin (θ) = - \frac{8}{9}

2 sin^{2} (x) + 5 sin (x) - 12 = 0

3 tan (x - \frac{π}{5}) - 1 = 0

What is the general solution for sin(θ)= 4/5 ,cos(θ)= 3/5 ?
The general solution for sin(θ)= 4/5 ,cos(θ)= 3/5 is No Solution for θ\in\mathbb{R}